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20153055635 = 54030611127
BaseRepresentation
bin10010110001001101…
…110011100110010011
31221000111112022002222
4102301031303212103
5312233140240020
613131433531255
71312261101146
oct226115634623
957014468088
1020153055635
118601968a89
123aa5273b2b
131b923065bb
14d9276805d
157ce400b25
hex4b1373993

20153055635 has 4 divisors (see below), whose sum is σ = 24183666768. Its totient is φ = 16122444504.

The previous prime is 20153055557. The next prime is 20153055667. The reversal of 20153055635 is 53655035102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20153055635 - 218 = 20152793491 is a prime.

It is a super-2 number, since 2×201530556352 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20153055595 and 20153055604.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2015305559 + ... + 2015305568.

It is an arithmetic number, because the mean of its divisors is an integer number (6045916692).

Almost surely, 220153055635 is an apocalyptic number.

20153055635 is a deficient number, since it is larger than the sum of its proper divisors (4030611133).

20153055635 is an equidigital number, since it uses as much as digits as its factorization.

20153055635 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4030611132.

The product of its (nonzero) digits is 67500, while the sum is 35.

The spelling of 20153055635 in words is "twenty billion, one hundred fifty-three million, fifty-five thousand, six hundred thirty-five".

Divisors: 1 5 4030611127 20153055635