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20153153 is a prime number
BaseRepresentation
bin100110011100…
…0001101000001
31101220212221002
41030320031001
520124400103
61555541345
7333204356
oct114701501
941825832
1020153153
11104153a9
1268ba855
134238057
14296862d
151b81488
hex1338341

20153153 has 2 divisors, whose sum is σ = 20153154. Its totient is φ = 20153152.

The previous prime is 20153141. The next prime is 20153191. The reversal of 20153153 is 35135102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19784704 + 368449 = 4448^2 + 607^2 .

It is a cyclic number.

It is not a de Polignac number, because 20153153 - 28 = 20152897 is a prime.

It is a super-2 number, since 2×201531532 = 812299151682818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20150153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10076576 + 10076577.

It is an arithmetic number, because the mean of its divisors is an integer number (10076577).

Almost surely, 220153153 is an apocalyptic number.

It is an amenable number.

20153153 is a deficient number, since it is larger than the sum of its proper divisors (1).

20153153 is an equidigital number, since it uses as much as digits as its factorization.

20153153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 20.

The square root of 20153153 is about 4489.2263253260. The cubic root of 20153153 is about 272.1328692321.

Adding to 20153153 its reverse (35135102), we get a palindrome (55288255).

It can be divided in two parts, 201 and 53153, that multiplied together give a triangular number (10683753 = T4622).

The spelling of 20153153 in words is "twenty million, one hundred fifty-three thousand, one hundred fifty-three".