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201532215551 = 1481136078471
BaseRepresentation
bin1011101110110001000…
…0011001000011111111
3201021012010102022002112
42323230100121003333
511300214221344201
6232325502444235
720363104365512
oct2735420310377
9637163368075
10201532215551
1178518755447
123308489367b
13160098b09b4
149a7b7acd79
155397c340bb
hex2eec4190ff

201532215551 has 4 divisors (see below), whose sum is σ = 201668295504. Its totient is φ = 201396135600.

The previous prime is 201532215527. The next prime is 201532215557. The reversal of 201532215551 is 155512235102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201532215551 is a prime.

It is a super-3 number, since 3×2015322155513 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201532215557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68037755 + ... + 68040716.

It is an arithmetic number, because the mean of its divisors is an integer number (50417073876).

Almost surely, 2201532215551 is an apocalyptic number.

201532215551 is a deficient number, since it is larger than the sum of its proper divisors (136079953).

201532215551 is a wasteful number, since it uses less digits than its factorization.

201532215551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 136079952.

The product of its (nonzero) digits is 15000, while the sum is 32.

The spelling of 201532215551 in words is "two hundred one billion, five hundred thirty-two million, two hundred fifteen thousand, five hundred fifty-one".

Divisors: 1 1481 136078471 201532215551