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201532423 = 491410453
BaseRepresentation
bin11000000001100…
…10010000000111
3112001012220111211
430000302100013
5403043014143
631555312251
74664666041
oct1400622007
9461186454
10201532423
11a383a324
12575ab687
13329a2971
141caa0a91
1512a5d49d
hexc032407

201532423 has 4 divisors (see below), whose sum is σ = 201943368. Its totient is φ = 201121480.

The previous prime is 201532393. The next prime is 201532469. The reversal of 201532423 is 324235102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201532423 - 25 = 201532391 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201532394 and 201532403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201532523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204736 + ... + 205717.

It is an arithmetic number, because the mean of its divisors is an integer number (50485842).

Almost surely, 2201532423 is an apocalyptic number.

201532423 is a deficient number, since it is larger than the sum of its proper divisors (410945).

201532423 is an equidigital number, since it uses as much as digits as its factorization.

201532423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 410944.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 201532423 is about 14196.2115721061. The cubic root of 201532423 is about 586.2933597376.

Adding to 201532423 its reverse (324235102), we get a palindrome (525767525).

The spelling of 201532423 in words is "two hundred one million, five hundred thirty-two thousand, four hundred twenty-three".

Divisors: 1 491 410453 201532423