Base | Representation |
---|---|
bin | 1001001010100010011110… |
… | …11110101101111001010001 |
3 | 2122100122020112002202110220 |
4 | 10211101033132231321101 |
5 | 10120142444410131301 |
6 | 110510150221543253 |
7 | 4150013025405405 |
oct | 445211736557121 |
9 | 78318215082426 |
10 | 20153320005201 |
11 | 646aa7a824239 |
12 | 2315a22114b29 |
13 | b325b062b0c6 |
14 | 4d95d6915105 |
15 | 24e37a16a936 |
hex | 12544f7ade51 |
20153320005201 has 8 divisors (see below), whose sum is σ = 27019552420224. Its totient is φ = 13361317130160.
The previous prime is 20153320005151. The next prime is 20153320005223. The reversal of 20153320005201 is 10250002335102.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20153320005201 - 210 = 20153320004177 is a prime.
It is a super-3 number, since 3×201533200052013 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (20153320005281) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18557384361 + ... + 18557385446.
It is an arithmetic number, because the mean of its divisors is an integer number (3377444052528).
Almost surely, 220153320005201 is an apocalyptic number.
It is an amenable number.
20153320005201 is a deficient number, since it is larger than the sum of its proper divisors (6866232415023).
20153320005201 is a wasteful number, since it uses less digits than its factorization.
20153320005201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37114769991.
The product of its (nonzero) digits is 1800, while the sum is 24.
The spelling of 20153320005201 in words is "twenty trillion, one hundred fifty-three billion, three hundred twenty million, five thousand, two hundred one".
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