Base | Representation |
---|---|
bin | 10010110001001110… |
… | …111011011111001101 |
3 | 1221000112002021000211 |
4 | 102301032323133031 |
5 | 312233224200333 |
6 | 13131444122421 |
7 | 1312263435502 |
oct | 226116733715 |
9 | 57015067024 |
10 | 20153350093 |
11 | 860204a238 |
12 | 3aa5396411 |
13 | 1b923aa636 |
14 | d928034a9 |
15 | 7ce45cecd |
hex | 4b13bb7cd |
20153350093 has 2 divisors, whose sum is σ = 20153350094. Its totient is φ = 20153350092.
The previous prime is 20153350057. The next prime is 20153350121. The reversal of 20153350093 is 39005335102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13943594889 + 6209755204 = 118083^2 + 78802^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20153350093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20153350003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10076675046 + 10076675047.
It is an arithmetic number, because the mean of its divisors is an integer number (10076675047).
Almost surely, 220153350093 is an apocalyptic number.
It is an amenable number.
20153350093 is a deficient number, since it is larger than the sum of its proper divisors (1).
20153350093 is an equidigital number, since it uses as much as digits as its factorization.
20153350093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12150, while the sum is 31.
Adding to 20153350093 its reverse (39005335102), we get a palindrome (59158685195).
The spelling of 20153350093 in words is "twenty billion, one hundred fifty-three million, three hundred fifty thousand, ninety-three".
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