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201535000453 = 1910607105287
BaseRepresentation
bin1011101110110001101…
…1000000111110000101
3201021012022122210021001
42323230123000332011
511300220430003303
6232330042253301
720363140144663
oct2735433007605
9637168583231
10201535000453
117851a287816
12330857b7231
131600a347477
149a7bcd5c33
1553980d431d
hex2eec6c0f85

201535000453 has 4 divisors (see below), whose sum is σ = 212142105760. Its totient is φ = 190927895148.

The previous prime is 201535000441. The next prime is 201535000481. The reversal of 201535000453 is 354000535102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201535000453 - 213 = 201534992261 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201535000753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5303552625 + ... + 5303552662.

It is an arithmetic number, because the mean of its divisors is an integer number (53035526440).

Almost surely, 2201535000453 is an apocalyptic number.

It is an amenable number.

201535000453 is a deficient number, since it is larger than the sum of its proper divisors (10607105307).

201535000453 is a wasteful number, since it uses less digits than its factorization.

201535000453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10607105306.

The product of its (nonzero) digits is 9000, while the sum is 28.

Adding to 201535000453 its reverse (354000535102), we get a palindrome (555535535555).

The spelling of 201535000453 in words is "two hundred one billion, five hundred thirty-five million, four hundred fifty-three", and thus it is an aban number.

Divisors: 1 19 10607105287 201535000453