Base | Representation |
---|---|
bin | 1011101110110010100… |
… | …0011110011111011011 |
3 | 201021012120022001211222 |
4 | 2323230220132133123 |
5 | 11300222330413433 |
6 | 232330250042255 |
7 | 20363212143002 |
oct | 2735450363733 |
9 | 637176261758 |
10 | 201538529243 |
11 | 78521277a77 |
12 | 33086a1938b |
13 | 1600acb16cc |
14 | 9a7c573c39 |
15 | 539857eb98 |
hex | 2eeca1e7db |
201538529243 has 2 divisors, whose sum is σ = 201538529244. Its totient is φ = 201538529242.
The previous prime is 201538529239. The next prime is 201538529287. The reversal of 201538529243 is 342925835102.
It is an a-pointer prime, because the next prime (201538529287) can be obtained adding 201538529243 to its sum of digits (44).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201538529243 - 22 = 201538529239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201538529194 and 201538529203.
It is not a weakly prime, because it can be changed into another prime (201538529293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100769264621 + 100769264622.
It is an arithmetic number, because the mean of its divisors is an integer number (100769264622).
Almost surely, 2201538529243 is an apocalyptic number.
201538529243 is a deficient number, since it is larger than the sum of its proper divisors (1).
201538529243 is an equidigital number, since it uses as much as digits as its factorization.
201538529243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 44.
The spelling of 201538529243 in words is "two hundred one billion, five hundred thirty-eight million, five hundred twenty-nine thousand, two hundred forty-three".
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