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201541211145 = 32514813024101
BaseRepresentation
bin1011101110110011001…
…0101101010000001001
3201021012202100022201200
42323230302231100021
511300224022224040
6232330423334413
720363244012651
oct2735462552011
9637182308650
10201541211145
1178522839a1a
12330878b1409
131600b710331
149a7ca71361
15539890e630
hex2eeccad409

201541211145 has 24 divisors (see below), whose sum is σ = 349574094792. Its totient is φ = 107416032000.

The previous prime is 201541211143. The next prime is 201541211153. The reversal of 201541211145 is 541112145102.

201541211145 is a `hidden beast` number, since 2 + 0 + 1 + 541 + 2 + 1 + 114 + 5 = 666.

201541211145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 1670520384 + 199870690761 = 40872^2 + 447069^2 .

It is not a de Polignac number, because 201541211145 - 21 = 201541211143 is a prime.

It is a super-2 number, since 2×2015412111452 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (201541211143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1445406 + ... + 1578695.

It is an arithmetic number, because the mean of its divisors is an integer number (14565587283).

Almost surely, 2201541211145 is an apocalyptic number.

It is an amenable number.

201541211145 is a deficient number, since it is larger than the sum of its proper divisors (148032883647).

201541211145 is a wasteful number, since it uses less digits than its factorization.

201541211145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3025593 (or 3025590 counting only the distinct ones).

The product of its (nonzero) digits is 1600, while the sum is 27.

Adding to 201541211145 its reverse (541112145102), we get a palindrome (742653356247).

It can be divided in two parts, 201541 and 211145, that added together give a triangular number (412686 = T908).

The spelling of 201541211145 in words is "two hundred one billion, five hundred forty-one million, two hundred eleven thousand, one hundred forty-five".

Divisors: 1 3 5 9 15 45 1481 4443 7405 13329 22215 66645 3024101 9072303 15120505 27216909 45361515 136084545 4478693581 13436080743 22393467905 40308242229 67180403715 201541211145