Base | Representation |
---|---|
bin | 10010110001010010… |
… | …100110101011010011 |
3 | 1221000120220012110212 |
4 | 102301102212223103 |
5 | 312234001012202 |
6 | 13131520514335 |
7 | 1312304560163 |
oct | 226122465323 |
9 | 57016805425 |
10 | 20154313427 |
11 | 8602647a86 |
12 | 3aa577b9ab |
13 | 1b92656c61 |
14 | d929b45a3 |
15 | 7ce59d652 |
hex | 4b14a6ad3 |
20154313427 has 2 divisors, whose sum is σ = 20154313428. Its totient is φ = 20154313426.
The previous prime is 20154313423. The next prime is 20154313471. The reversal of 20154313427 is 72431345102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20154313427 - 22 = 20154313423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20154313393 and 20154313402.
It is not a weakly prime, because it can be changed into another prime (20154313423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077156713 + 10077156714.
It is an arithmetic number, because the mean of its divisors is an integer number (10077156714).
Almost surely, 220154313427 is an apocalyptic number.
20154313427 is a deficient number, since it is larger than the sum of its proper divisors (1).
20154313427 is an equidigital number, since it uses as much as digits as its factorization.
20154313427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 20154313427 its reverse (72431345102), we get a palindrome (92585658529).
The spelling of 20154313427 in words is "twenty billion, one hundred fifty-four million, three hundred thirteen thousand, four hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •