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20154313513 = 85632353651
BaseRepresentation
bin10010110001010010…
…100110101100101001
31221000120220012121001
4102301102212230221
5312234001013023
613131520515001
71312304560345
oct226122465451
957016805531
1020154313513
118602648054
123aa577ba61
131b92656cc9
14d929b4625
157ce59d6ad
hex4b14a6b29

20154313513 has 4 divisors (see below), whose sum is σ = 20156675728. Its totient is φ = 20151951300.

The previous prime is 20154313511. The next prime is 20154313561. The reversal of 20154313513 is 31531345102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20154313513 - 21 = 20154313511 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20154313511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1168263 + ... + 1185388.

It is an arithmetic number, because the mean of its divisors is an integer number (5039168932).

Almost surely, 220154313513 is an apocalyptic number.

It is an amenable number.

20154313513 is a deficient number, since it is larger than the sum of its proper divisors (2362215).

20154313513 is an equidigital number, since it uses as much as digits as its factorization.

20154313513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2362214.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 20154313513 its reverse (31531345102), we get a palindrome (51685658615).

The spelling of 20154313513 in words is "twenty billion, one hundred fifty-four million, three hundred thirteen thousand, five hundred thirteen".

Divisors: 1 8563 2353651 20154313513