Base | Representation |
---|---|
bin | 10010110001010010… |
… | …101001010011010101 |
3 | 1221000120220202020011 |
4 | 102301102221103111 |
5 | 312234001333211 |
6 | 13131521040221 |
7 | 1312304633425 |
oct | 226122512325 |
9 | 57016822204 |
10 | 20154324181 |
11 | 8602655072 |
12 | 3aa5786071 |
13 | 1b9265bb14 |
14 | d929b8485 |
15 | 7ce5a1921 |
hex | 4b14a94d5 |
20154324181 has 2 divisors, whose sum is σ = 20154324182. Its totient is φ = 20154324180.
The previous prime is 20154324167. The next prime is 20154324227. The reversal of 20154324181 is 18142345102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12190368100 + 7963956081 = 110410^2 + 89241^2 .
It is a cyclic number.
It is not a de Polignac number, because 20154324181 - 27 = 20154324053 is a prime.
It is a super-2 number, since 2×201543241812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20154324581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077162090 + 10077162091.
It is an arithmetic number, because the mean of its divisors is an integer number (10077162091).
Almost surely, 220154324181 is an apocalyptic number.
It is an amenable number.
20154324181 is a deficient number, since it is larger than the sum of its proper divisors (1).
20154324181 is an equidigital number, since it uses as much as digits as its factorization.
20154324181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 20154324181 its reverse (18142345102), we get a palindrome (38296669283).
The spelling of 20154324181 in words is "twenty billion, one hundred fifty-four million, three hundred twenty-four thousand, one hundred eighty-one".
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