2016032000033 has 4 divisors (see below), whose sum is σ = 2134622117700. Its totient is φ = 1897441882368.

The previous prime is 2016032000029. The next prime is 2016032000089. The reversal of 2016032000033 is 3300002306102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1509340016704 + 506691983329 = 1228552^2 + 711823^2 .

It is a cyclic number.

It is not a de Polignac number, because 2016032000033 - 2² = 2016032000029 is a prime.

It is a super-2 number, since 2×2016032000033² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2016031999969 and 2016032000014.

It is not an unprimeable number, because it can be changed into a prime (2016032000023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59295058808 + ... + 59295058841.

It is an arithmetic number, because the mean of its divisors is an integer number (533655529425).

Almost surely, 2^{2016032000033} is an apocalyptic number.

It is an amenable number.

2016032000033 is a deficient number, since it is larger than the sum of its proper divisors (118590117667).

2016032000033 is a wasteful number, since it uses less digits than its factorization.

2016032000033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118590117666.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 2016032000033 its reverse (3300002306102), we get a palindrome (5316034306135).

The spelling of 2016032000033 in words is "two trillion, sixteen billion, thirty-two million, thirty-three", and thus it is an aban number and an uban number.