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201613440541 is a prime number
BaseRepresentation
bin1011101111000100011…
…0001111011000011101
3201021101210020221211111
42323301012033120131
511300401020044131
6232341523422021
720365111653202
oct2736106173035
9637353227744
10201613440541
117855a592a37
12330a7b24911
131602067c816
149a884b3ca9
15539ee2aab1
hex2ef118f61d

201613440541 has 2 divisors, whose sum is σ = 201613440542. Its totient is φ = 201613440540.

The previous prime is 201613440529. The next prime is 201613440577. The reversal of 201613440541 is 145044316102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 185132272900 + 16481167641 = 430270^2 + 128379^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201613440541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201613440341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100806720270 + 100806720271.

It is an arithmetic number, because the mean of its divisors is an integer number (100806720271).

Almost surely, 2201613440541 is an apocalyptic number.

It is an amenable number.

201613440541 is a deficient number, since it is larger than the sum of its proper divisors (1).

201613440541 is an equidigital number, since it uses as much as digits as its factorization.

201613440541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 201613440541 its reverse (145044316102), we get a palindrome (346657756643).

The spelling of 201613440541 in words is "two hundred one billion, six hundred thirteen million, four hundred forty thousand, five hundred forty-one".