Base | Representation |
---|---|
bin | 11101010101101011100… |
… | …100001000000001111011 |
3 | 21010202000120011221221022 |
4 | 131111223210020001323 |
5 | 231013030414402021 |
6 | 4142112013133055 |
7 | 265442635511441 |
oct | 35255344100173 |
9 | 7122016157838 |
10 | 2016144294011 |
11 | 708050990931 |
12 | 2868aa78a18b |
13 | 11817719c273 |
14 | 6d820a62b91 |
15 | 376a04c71ab |
hex | 1d56b90807b |
2016144294011 has 2 divisors, whose sum is σ = 2016144294012. Its totient is φ = 2016144294010.
The previous prime is 2016144293851. The next prime is 2016144294013. The reversal of 2016144294011 is 1104924416102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2016144294011 - 222 = 2016140099707 is a prime.
It is a super-2 number, since 2×20161442940112 (a number of 25 digits) contains 22 as substring.
Together with 2016144294013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2016144294013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1008072147005 + 1008072147006.
It is an arithmetic number, because the mean of its divisors is an integer number (1008072147006).
Almost surely, 22016144294011 is an apocalyptic number.
2016144294011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2016144294011 is an equidigital number, since it uses as much as digits as its factorization.
2016144294011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 35.
The spelling of 2016144294011 in words is "two trillion, sixteen billion, one hundred forty-four million, two hundred ninety-four thousand, eleven".
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