Base | Representation |
---|---|
bin | 1001001010110010000001… |
… | …11101110100000001011111 |
3 | 2122101102210012101020010211 |
4 | 10211121000331310001133 |
5 | 10120312043101324434 |
6 | 110514050334513251 |
7 | 4150426614024451 |
oct | 445310075640137 |
9 | 78342705336124 |
10 | 20161666433119 |
11 | 64735730a7052 |
12 | 2317571365827 |
13 | b33310876553 |
14 | 4d9b891da2d1 |
15 | 24e6b7c96464 |
hex | 125640f7405f |
20161666433119 has 2 divisors, whose sum is σ = 20161666433120. Its totient is φ = 20161666433118.
The previous prime is 20161666433113. The next prime is 20161666433197. The reversal of 20161666433119 is 91133466616102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20161666433119 - 27 = 20161666432991 is a prime.
It is a super-2 number, since 2×201616664331192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20161666433113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10080833216559 + 10080833216560.
It is an arithmetic number, because the mean of its divisors is an integer number (10080833216560).
Almost surely, 220161666433119 is an apocalyptic number.
20161666433119 is a deficient number, since it is larger than the sum of its proper divisors (1).
20161666433119 is an equidigital number, since it uses as much as digits as its factorization.
20161666433119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 839808, while the sum is 49.
The spelling of 20161666433119 in words is "twenty trillion, one hundred sixty-one billion, six hundred sixty-six million, four hundred thirty-three thousand, one hundred nineteen".
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