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20163731023153 is a prime number
BaseRepresentation
bin1001001010110101111000…
…00001100110010100110001
32122101122010002021021020101
410211122330001212110301
510120330310120220103
6110515031250112401
74150532023531414
oct445327401462461
978348102237211
1020163731023153
11647443254a103
122317a4887b701
13b3357c516b63
144d9d034a9b7b
1524e789166a1d
hex1256bc066531

20163731023153 has 2 divisors, whose sum is σ = 20163731023154. Its totient is φ = 20163731023152.

The previous prime is 20163731023151. The next prime is 20163731023193. The reversal of 20163731023153 is 35132013736102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12284863770529 + 7878867252624 = 3504977^2 + 2806932^2 .

It is a cyclic number.

It is not a de Polignac number, because 20163731023153 - 21 = 20163731023151 is a prime.

It is a super-2 number, since 2×201637310231532 (a number of 27 digits) contains 22 as substring.

Together with 20163731023151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (20163731023151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10081865511576 + 10081865511577.

It is an arithmetic number, because the mean of its divisors is an integer number (10081865511577).

Almost surely, 220163731023153 is an apocalyptic number.

It is an amenable number.

20163731023153 is a deficient number, since it is larger than the sum of its proper divisors (1).

20163731023153 is an equidigital number, since it uses as much as digits as its factorization.

20163731023153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 37.

Adding to 20163731023153 its reverse (35132013736102), we get a palindrome (55295744759255).

The spelling of 20163731023153 in words is "twenty trillion, one hundred sixty-three billion, seven hundred thirty-one million, twenty-three thousand, one hundred fifty-three".