Base | Representation |
---|---|
bin | 1001001011010000101101… |
… | …10011100100100000001011 |
3 | 2122110000022012101000110122 |
4 | 10211220112303210200023 |
5 | 10121044312034133334 |
6 | 110525413054333455 |
7 | 4151552044225562 |
oct | 445502663444013 |
9 | 78400265330418 |
10 | 20178138974219 |
11 | 647a556453a86 |
12 | 231a7a9aba28b |
13 | b34a374bc3a5 |
14 | 4da8acc16bd9 |
15 | 24ed2dece32e |
hex | 125a16ce480b |
20178138974219 has 2 divisors, whose sum is σ = 20178138974220. Its totient is φ = 20178138974218.
The previous prime is 20178138974167. The next prime is 20178138974221. The reversal of 20178138974219 is 91247983187102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20178138974219 is a prime.
It is a super-2 number, since 2×201781389742192 (a number of 27 digits) contains 22 as substring.
Together with 20178138974221, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20178138973219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10089069487109 + 10089069487110.
It is an arithmetic number, because the mean of its divisors is an integer number (10089069487110).
Almost surely, 220178138974219 is an apocalyptic number.
20178138974219 is a deficient number, since it is larger than the sum of its proper divisors (1).
20178138974219 is an equidigital number, since it uses as much as digits as its factorization.
20178138974219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12192768, while the sum is 62.
The spelling of 20178138974219 in words is "twenty trillion, one hundred seventy-eight billion, one hundred thirty-eight million, nine hundred seventy-four thousand, two hundred nineteen".
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