Base | Representation |
---|---|
bin | 11101010111100000110… |
… | …010100001110101100001 |
3 | 21010221002121220011212001 |
4 | 131113200302201311201 |
5 | 231031042404112001 |
6 | 4143035110404001 |
7 | 265542446333011 |
oct | 35274062416541 |
9 | 7127077804761 |
10 | 2018111004001 |
11 | 708970060194 |
12 | 287159360601 |
13 | 1183cb78bca1 |
14 | 6d969d33c41 |
15 | 37767eb1001 |
hex | 1d5e0ca1d61 |
2018111004001 has 2 divisors, whose sum is σ = 2018111004002. Its totient is φ = 2018111004000.
The previous prime is 2018111003959. The next prime is 2018111004043. The reversal of 2018111004001 is 1004001118102.
It is a balanced prime because it is at equal distance from previous prime (2018111003959) and next prime (2018111004043).
It can be written as a sum of positive squares in only one way, i.e., 1095003187776 + 923107816225 = 1046424^2 + 960785^2 .
It is a cyclic number.
It is not a de Polignac number, because 2018111004001 - 213 = 2018110995809 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2018111004001.
It is not a weakly prime, because it can be changed into another prime (2018111004061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1009055502000 + 1009055502001.
It is an arithmetic number, because the mean of its divisors is an integer number (1009055502001).
Almost surely, 22018111004001 is an apocalyptic number.
It is an amenable number.
2018111004001 is a deficient number, since it is larger than the sum of its proper divisors (1).
2018111004001 is an equidigital number, since it uses as much as digits as its factorization.
2018111004001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
The spelling of 2018111004001 in words is "two trillion, eighteen billion, one hundred eleven million, four thousand, one".
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