Base | Representation |
---|---|
bin | 1001001011011011000100… |
… | …11000000100011011000001 |
3 | 2122110112122212210212201212 |
4 | 10211231202120010123001 |
5 | 10121142210130110031 |
6 | 110532133053135505 |
7 | 4152136642405451 |
oct | 445554230043301 |
9 | 78415585725655 |
10 | 20183701800641 |
11 | 6481950529895 |
12 | 231b8a0a8a595 |
13 | b35412b2c662 |
14 | 4dac79945d61 |
15 | 25005755e12b |
hex | 125b626046c1 |
20183701800641 has 2 divisors, whose sum is σ = 20183701800642. Its totient is φ = 20183701800640.
The previous prime is 20183701800599. The next prime is 20183701800643. The reversal of 20183701800641 is 14600810738102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19982822146225 + 200879654416 = 4470215^2 + 448196^2 .
It is a cyclic number.
It is not a de Polignac number, because 20183701800641 - 210 = 20183701799617 is a prime.
Together with 20183701800643, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20183701800643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10091850900320 + 10091850900321.
It is an arithmetic number, because the mean of its divisors is an integer number (10091850900321).
Almost surely, 220183701800641 is an apocalyptic number.
It is an amenable number.
20183701800641 is a deficient number, since it is larger than the sum of its proper divisors (1).
20183701800641 is an equidigital number, since it uses as much as digits as its factorization.
20183701800641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 41.
The spelling of 20183701800641 in words is "twenty trillion, one hundred eighty-three billion, seven hundred one million, eight hundred thousand, six hundred forty-one".
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