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20191370325853 is a prime number
BaseRepresentation
bin1001001011101001010110…
…11101001010111101011101
32122111021110022111022201011
410211310223131022331131
510121303411300411403
6110535442032215221
74152530656656016
oct445645335127535
978437408438634
1020191370325853
116485126185331
12232128109a511
13b360657a463c
144db3a61a600d
152503558cea6d
hex125d2b74af5d

20191370325853 has 2 divisors, whose sum is σ = 20191370325854. Its totient is φ = 20191370325852.

The previous prime is 20191370325803. The next prime is 20191370325857. The reversal of 20191370325853 is 35852307319102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12792089019609 + 7399281306244 = 3576603^2 + 2720162^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20191370325853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20191370325797 and 20191370325806.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20191370325857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10095685162926 + 10095685162927.

It is an arithmetic number, because the mean of its divisors is an integer number (10095685162927).

Almost surely, 220191370325853 is an apocalyptic number.

It is an amenable number.

20191370325853 is a deficient number, since it is larger than the sum of its proper divisors (1).

20191370325853 is an equidigital number, since it uses as much as digits as its factorization.

20191370325853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 49.

The spelling of 20191370325853 in words is "twenty trillion, one hundred ninety-one billion, three hundred seventy million, three hundred twenty-five thousand, eight hundred fifty-three".