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2020120221111 = 32293293664809
BaseRepresentation
bin11101011001011000100…
…011000101010110110111
321011010021122120222120120
4131121120203011112313
5231044201234033421
64144010323103023
7265643314363566
oct35313043052667
97133248528516
102020120221111
117098012227a3
1228761a211a73
1311865bb12755
146dabab0bbdd
15378345948c6
hex1d6588c55b7

2020120221111 has 8 divisors (see below), whose sum is σ = 2694668296560. Its totient is φ = 1346159479872.

The previous prime is 2020120221107. The next prime is 2020120221179. The reversal of 2020120221111 is 1111220210202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2020120221111 - 22 = 2020120221107 is a prime.

It is a super-4 number, since 4×20201202211114 (a number of 50 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2020120221181) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 146825526 + ... + 146839283.

It is an arithmetic number, because the mean of its divisors is an integer number (336833537070).

Almost surely, 22020120221111 is an apocalyptic number.

2020120221111 is a deficient number, since it is larger than the sum of its proper divisors (674548075449).

2020120221111 is a wasteful number, since it uses less digits than its factorization.

2020120221111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 293667105.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 2020120221111 its reverse (1111220210202), we get a palindrome (3131340431313).

The spelling of 2020120221111 in words is "two trillion, twenty billion, one hundred twenty million, two hundred twenty-one thousand, one hundred eleven".

Divisors: 1 3 2293 6879 293664809 880994427 673373407037 2020120221111