Base | Representation |
---|---|
bin | 101101111011101010011100… |
… | …000100011110101101001111 |
3 | 222111021011120021222211110021 |
4 | 231323222130010132231033 |
5 | 202434231300204020421 |
6 | 1553351025434323011 |
7 | 60356615261066002 |
oct | 5573523404365517 |
9 | 874234507884407 |
10 | 202012110220111 |
11 | 59404944857804 |
12 | 1a7a7372b89467 |
13 | 8894877769369 |
14 | 37c561c9c3539 |
15 | 1854bea310341 |
hex | b7ba9c11eb4f |
202012110220111 has 2 divisors, whose sum is σ = 202012110220112. Its totient is φ = 202012110220110.
The previous prime is 202012110220097. The next prime is 202012110220153. The reversal of 202012110220111 is 111022011210202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 202012110220111 - 29 = 202012110219599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (202012110220511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101006055110055 + 101006055110056.
It is an arithmetic number, because the mean of its divisors is an integer number (101006055110056).
Almost surely, 2202012110220111 is an apocalyptic number.
202012110220111 is a deficient number, since it is larger than the sum of its proper divisors (1).
202012110220111 is an equidigital number, since it uses as much as digits as its factorization.
202012110220111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 202012110220111 its reverse (111022011210202), we get a palindrome (313034121430313).
Subtracting from 202012110220111 its reverse (111022011210202), we obtain a palindrome (90990099009909).
The spelling of 202012110220111 in words is "two hundred two trillion, twelve billion, one hundred ten million, two hundred twenty thousand, one hundred eleven".
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