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2020130113 is a prime number
BaseRepresentation
bin111100001101000…
…1011110101000001
312012210020020112211
41320122023311001
513114123130423
6532242222121
7101026552111
oct17032136501
95183206484
102020130113
11947346721
12484654941
132626a4a81
14152419041
15bc53c10d
hex7868bd41

2020130113 has 2 divisors, whose sum is σ = 2020130114. Its totient is φ = 2020130112.

The previous prime is 2020130023. The next prime is 2020130117. The reversal of 2020130113 is 3110310202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1953021249 + 67108864 = 44193^2 + 8192^2 .

It is a cyclic number.

It is not a de Polignac number, because 2020130113 - 213 = 2020121921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2020130093 and 2020130102.

It is not a weakly prime, because it can be changed into another prime (2020130117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010065056 + 1010065057.

It is an arithmetic number, because the mean of its divisors is an integer number (1010065057).

Almost surely, 22020130113 is an apocalyptic number.

It is an amenable number.

2020130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2020130113 is an equidigital number, since it uses as much as digits as its factorization.

2020130113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 2020130113 is about 44945.8575733070. The cubic root of 2020130113 is about 1264.1340056562.

Adding to 2020130113 its reverse (3110310202), we get a palindrome (5130440315).

The spelling of 2020130113 in words is "two billion, twenty million, one hundred thirty thousand, one hundred thirteen".