Search a number
-
+
2020201331103 = 32840532670539
BaseRepresentation
bin11101011001011101011…
…000011111100110011111
321011010111022012210120100
4131121131120133212133
5231044333020043403
64144022341352143
7265645320662064
oct35313530374637
97133438183510
102020201331103
11709842a9194a
12287641408653
13118672871127
146dac77c2c6b
153783b7672a3
hex1d65d61f99f

2020201331103 has 12 divisors (see below), whose sum is σ = 2918104399080. Its totient is φ = 1346784359856.

The previous prime is 2020201331069. The next prime is 2020201331167. The reversal of 2020201331103 is 3011331020202.

It is not a de Polignac number, because 2020201331103 - 222 = 2020197136799 is a prime.

It is a super-3 number, since 3×20202013311033 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2020201331173) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 578793 + ... + 2091746.

It is an arithmetic number, because the mean of its divisors is an integer number (243175366590).

Almost surely, 22020201331103 is an apocalyptic number.

2020201331103 is a deficient number, since it is larger than the sum of its proper divisors (897903067977).

2020201331103 is a wasteful number, since it uses less digits than its factorization.

2020201331103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2754598 (or 2754595 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 2020201331103 its reverse (3011331020202), we get a palindrome (5031532351305).

The spelling of 2020201331103 in words is "two trillion, twenty billion, two hundred one million, three hundred thirty-one thousand, one hundred three".

Divisors: 1 3 9 84053 252159 756477 2670539 8011617 24034851 224466814567 673400443701 2020201331103