Base | Representation |
---|---|
bin | 11101011001100101000… |
… | …111100110011001001011 |
3 | 21011010211100102202202001 |
4 | 131121211013212121023 |
5 | 231100114231321303 |
6 | 4144043255251431 |
7 | 265651455114004 |
oct | 35314507463113 |
9 | 7133740382661 |
10 | 2020331120203 |
11 | 7098aa27a370 |
12 | 287678979b77 |
13 | 118693714906 |
14 | 6dadab2a1ab |
15 | 37847d5331d |
hex | 1d6651e664b |
2020331120203 has 8 divisors (see below), whose sum is σ = 2204008349760. Its totient is φ = 1836655684680.
The previous prime is 2020331120177. The next prime is 2020331120209. The reversal of 2020331120203 is 3020211330202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2020331120203 - 213 = 2020331112011 is a prime.
It is a super-2 number, since 2×20203311202032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2020331120209) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3188476 + ... + 3769222.
It is an arithmetic number, because the mean of its divisors is an integer number (275501043720).
Almost surely, 22020331120203 is an apocalyptic number.
2020331120203 is a deficient number, since it is larger than the sum of its proper divisors (183677229557).
2020331120203 is a wasteful number, since it uses less digits than its factorization.
2020331120203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 897017.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 2020331120203 its reverse (3020211330202), we get a palindrome (5040542450405).
The spelling of 2020331120203 in words is "two trillion, twenty billion, three hundred thirty-one million, one hundred twenty thousand, two hundred three".
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