Base | Representation |
---|---|
bin | 11101011001101001111… |
… | …001111110010000101111 |
3 | 21011011000221120010121021 |
4 | 131121221321332100233 |
5 | 231100300311342111 |
6 | 4144055244515011 |
7 | 265653451555054 |
oct | 35315171762057 |
9 | 7134027503537 |
10 | 2020411434031 |
11 | 709940645331 |
12 | 28769b84ba67 |
13 | 1186a7254aa3 |
14 | 6db0767502b |
15 | 3784ee19d71 |
hex | 1d669e7e42f |
2020411434031 has 2 divisors, whose sum is σ = 2020411434032. Its totient is φ = 2020411434030.
The previous prime is 2020411434011. The next prime is 2020411434037. The reversal of 2020411434031 is 1304341140202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2020411434031 - 225 = 2020377879599 is a prime.
It is a super-2 number, since 2×20204114340312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2020411433987 and 2020411434005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2020411434037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010205717015 + 1010205717016.
It is an arithmetic number, because the mean of its divisors is an integer number (1010205717016).
Almost surely, 22020411434031 is an apocalyptic number.
2020411434031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2020411434031 is an equidigital number, since it uses as much as digits as its factorization.
2020411434031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2020411434031 its reverse (1304341140202), we get a palindrome (3324752574233).
The spelling of 2020411434031 in words is "two trillion, twenty billion, four hundred eleven million, four hundred thirty-four thousand, thirty-one".
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