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2020411434121 = 31392916588079
BaseRepresentation
bin11101011001101001111…
…001111110010010001001
321011011000221120010201121
4131121221321332102021
5231100300311342441
64144055244515241
7265653451555243
oct35315171762211
97134027503647
102020411434121
11709940645403
1228769b84bb21
131186a7254b42
146db07675093
153784ee19dd1
hex1d669e7e489

2020411434121 has 8 divisors (see below), whose sum is σ = 2086116940800. Its totient is φ = 1954739111520.

The previous prime is 2020411434053. The next prime is 2020411434143. The reversal of 2020411434121 is 1214341140202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2020411434121 - 235 = 1986051695753 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2020411434161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8172241 + ... + 8415838.

It is an arithmetic number, because the mean of its divisors is an integer number (260764617600).

Almost surely, 22020411434121 is an apocalyptic number.

It is an amenable number.

2020411434121 is a deficient number, since it is larger than the sum of its proper divisors (65705506679).

2020411434121 is a wasteful number, since it uses less digits than its factorization.

2020411434121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16592039.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2020411434121 its reverse (1214341140202), we get a palindrome (3234752574323).

The spelling of 2020411434121 in words is "two trillion, twenty billion, four hundred eleven million, four hundred thirty-four thousand, one hundred twenty-one".

Divisors: 1 31 3929 121799 16588079 514230449 65174562391 2020411434121