Base | Representation |
---|---|
bin | 1001001100001100000011… |
… | …11100000010101011001111 |
3 | 2122120001112201122010210121 |
4 | 10212012001330002223033 |
5 | 10122110040242100033 |
6 | 110552202451045411 |
7 | 4154060445116611 |
oct | 446060174025317 |
9 | 78501481563717 |
10 | 20210001128143 |
11 | 64920168438a2 |
12 | 2324a005a0867 |
13 | b37a445c69c8 |
14 | 4dc2526b6db1 |
15 | 250a9633c62d |
hex | 126181f02acf |
20210001128143 has 2 divisors, whose sum is σ = 20210001128144. Its totient is φ = 20210001128142.
The previous prime is 20210001128131. The next prime is 20210001128167. The reversal of 20210001128143 is 34182110001202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20210001128143 - 25 = 20210001128111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20210001128173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105000564071 + 10105000564072.
It is an arithmetic number, because the mean of its divisors is an integer number (10105000564072).
Almost surely, 220210001128143 is an apocalyptic number.
20210001128143 is a deficient number, since it is larger than the sum of its proper divisors (1).
20210001128143 is an equidigital number, since it uses as much as digits as its factorization.
20210001128143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 20210001128143 its reverse (34182110001202), we get a palindrome (54392111129345).
The spelling of 20210001128143 in words is "twenty trillion, two hundred ten billion, one million, one hundred twenty-eight thousand, one hundred forty-three".
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