Base | Representation |
---|---|
bin | 101101111100111100011001… |
… | …011001000101100110011111 |
3 | 222111120120201022002112211001 |
4 | 231330330121121011212133 |
5 | 202442202012200321343 |
6 | 1553455302040411131 |
7 | 60366152115643312 |
oct | 5574743131054637 |
9 | 874516638075731 |
10 | 202100112120223 |
11 | 594391a3609879 |
12 | 1a800432776aa7 |
13 | 889cc6062b0c5 |
14 | 37c99aa39c979 |
15 | 185714b05244d |
hex | b7cf1964599f |
202100112120223 has 2 divisors, whose sum is σ = 202100112120224. Its totient is φ = 202100112120222.
The previous prime is 202100112120217. The next prime is 202100112120227. The reversal of 202100112120223 is 322021211001202.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-202100112120223 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 202100112120223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (202100112120227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101050056060111 + 101050056060112.
It is an arithmetic number, because the mean of its divisors is an integer number (101050056060112).
Almost surely, 2202100112120223 is an apocalyptic number.
202100112120223 is a deficient number, since it is larger than the sum of its proper divisors (1).
202100112120223 is an equidigital number, since it uses as much as digits as its factorization.
202100112120223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 202100112120223 its reverse (322021211001202), we get a palindrome (524121323121425).
The spelling of 202100112120223 in words is "two hundred two trillion, one hundred billion, one hundred twelve million, one hundred twenty thousand, two hundred twenty-three".
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