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20210031223 is a prime number
BaseRepresentation
bin10010110100100111…
…001001101001110111
31221011110201221220221
4102310213021221313
5312342231444343
613141231035211
71313552300554
oct226447115167
957143657827
1020210031223
118631043648
123b0036bb07
131ba1064a75
14d9a159a2b
157d44075ed
hex4b49c9a77

20210031223 has 2 divisors, whose sum is σ = 20210031224. Its totient is φ = 20210031222.

The previous prime is 20210031209. The next prime is 20210031263. The reversal of 20210031223 is 32213001202.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20210031223 is a prime.

It is a super-4 number, since 4×202100312234 (a number of 42 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20210031197 and 20210031206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20210031263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105015611 + 10105015612.

It is an arithmetic number, because the mean of its divisors is an integer number (10105015612).

Almost surely, 220210031223 is an apocalyptic number.

20210031223 is a deficient number, since it is larger than the sum of its proper divisors (1).

20210031223 is an equidigital number, since it uses as much as digits as its factorization.

20210031223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 20210031223 its reverse (32213001202), we get a palindrome (52423032425).

The spelling of 20210031223 in words is "twenty billion, two hundred ten million, thirty-one thousand, two hundred twenty-three".