Base | Representation |
---|---|
bin | 1001001100001100001111… |
… | …10101101010101010111011 |
3 | 2122120001210121220110102222 |
4 | 10212012013311222222323 |
5 | 10122110241112322001 |
6 | 110552220344514255 |
7 | 4154063056413416 |
oct | 446060765525273 |
9 | 78501717813388 |
10 | 20210100120251 |
11 | 6492067707058 |
12 | 2324a2977b98b |
13 | b37a5bc76812 |
14 | 4dc2618c4b7d |
15 | 250a9ed9361b |
hex | 126187d6aabb |
20210100120251 has 2 divisors, whose sum is σ = 20210100120252. Its totient is φ = 20210100120250.
The previous prime is 20210100120233. The next prime is 20210100120257. The reversal of 20210100120251 is 15202100101202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20210100120251 - 214 = 20210100103867 is a prime.
It is a super-3 number, since 3×202101001202513 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (20210100120257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105050060125 + 10105050060126.
It is an arithmetic number, because the mean of its divisors is an integer number (10105050060126).
Almost surely, 220210100120251 is an apocalyptic number.
20210100120251 is a deficient number, since it is larger than the sum of its proper divisors (1).
20210100120251 is an equidigital number, since it uses as much as digits as its factorization.
20210100120251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 20210100120251 its reverse (15202100101202), we get a palindrome (35412200221453).
The spelling of 20210100120251 in words is "twenty trillion, two hundred ten billion, one hundred million, one hundred twenty thousand, two hundred fifty-one".
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