Base | Representation |
---|---|
bin | 11101011010001101100… |
… | …101101111101011101101 |
3 | 21011012120200002002022020 |
4 | 131122031211233223231 |
5 | 231103012042024323 |
6 | 4144234512340353 |
7 | 266004341334432 |
oct | 35321545575355 |
9 | 7135520062266 |
10 | 2021010111213 |
11 | 70a11857a365 |
12 | 2878282446b9 |
13 | 1187712a9542 |
14 | 6db62d95b89 |
15 | 37887775ae3 |
hex | 1d68d96faed |
2021010111213 has 8 divisors (see below), whose sum is σ = 2694690444000. Its totient is φ = 1347334926288.
The previous prime is 2021010111187. The next prime is 2021010111221. The reversal of 2021010111213 is 3121110101202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2021010111213 - 29 = 2021010110701 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2021010111192 and 2021010111201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2021010111293) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 252018 + ... + 2026211.
It is an arithmetic number, because the mean of its divisors is an integer number (336836305500).
Almost surely, 22021010111213 is an apocalyptic number.
It is an amenable number.
2021010111213 is a deficient number, since it is larger than the sum of its proper divisors (673680332787).
2021010111213 is a wasteful number, since it uses less digits than its factorization.
2021010111213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2573931.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 2021010111213 its reverse (3121110101202), we get a palindrome (5142120212415).
The spelling of 2021010111213 in words is "two trillion, twenty-one billion, ten million, one hundred eleven thousand, two hundred thirteen".
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