Base | Representation |
---|---|
bin | 11101011010010011100… |
… | …110100111001110110011 |
3 | 21011012211200220212111100 |
4 | 131122103212213032303 |
5 | 231103213404031120 |
6 | 4144252515015443 |
7 | 266010005026656 |
oct | 35322346471663 |
9 | 7135750825440 |
10 | 2021111002035 |
11 | 70a16a51a104 |
12 | 287855b9a583 |
13 | 118789172658 |
14 | 6db7253989d |
15 | 37891554490 |
hex | 1d6939a73b3 |
2021111002035 has 36 divisors (see below), whose sum is σ = 3697345474992. Its totient is φ = 1021192919136.
The previous prime is 2021111002033. The next prime is 2021111002139. The reversal of 2021111002035 is 5302001111202.
It is not a de Polignac number, because 2021111002035 - 21 = 2021111002033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2021111001999 and 2021111002017.
It is not an unprimeable number, because it can be changed into a prime (2021111002033) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 62190927 + ... + 62223416.
It is an arithmetic number, because the mean of its divisors is an integer number (102704040972).
Almost surely, 22021111002035 is an apocalyptic number.
2021111002035 is a deficient number, since it is larger than the sum of its proper divisors (1676234472957).
2021111002035 is a wasteful number, since it uses less digits than its factorization.
2021111002035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124414392 (or 124414370 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
Adding to 2021111002035 its reverse (5302001111202), we get a palindrome (7323112113237).
The spelling of 2021111002035 in words is "two trillion, twenty-one billion, one hundred eleven million, two thousand, thirty-five".
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