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2021113302017 is a prime number
BaseRepresentation
bin11101011010010011101…
…111011000110000000001
321011012211212020201110212
4131122103233120300001
5231103220001131032
64144253040203505
7266010033416315
oct35322357306001
97135755221425
102021113302017
1170a170850117
12287856909595
131187897994a4
146db72977b45
153789185abb2
hex1d693bd8c01

2021113302017 has 2 divisors, whose sum is σ = 2021113302018. Its totient is φ = 2021113302016.

The previous prime is 2021113302001. The next prime is 2021113302037. The reversal of 2021113302017 is 7102033111202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2020878323776 + 234978241 = 1421576^2 + 15329^2 .

It is a cyclic number.

It is not a de Polignac number, because 2021113302017 - 24 = 2021113302001 is a prime.

It is a super-2 number, since 2×20211133020172 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2021113301983 and 2021113302001.

It is not a weakly prime, because it can be changed into another prime (2021113302037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010556651008 + 1010556651009.

It is an arithmetic number, because the mean of its divisors is an integer number (1010556651009).

Almost surely, 22021113302017 is an apocalyptic number.

It is an amenable number.

2021113302017 is a deficient number, since it is larger than the sum of its proper divisors (1).

2021113302017 is an equidigital number, since it uses as much as digits as its factorization.

2021113302017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 2021113302017 its reverse (7102033111202), we get a palindrome (9123146413219).

The spelling of 2021113302017 in words is "two trillion, twenty-one billion, one hundred thirteen million, three hundred two thousand, seventeen".