Base | Representation |
---|---|
bin | 11101011010010011101… |
… | …111011000110000000001 |
3 | 21011012211212020201110212 |
4 | 131122103233120300001 |
5 | 231103220001131032 |
6 | 4144253040203505 |
7 | 266010033416315 |
oct | 35322357306001 |
9 | 7135755221425 |
10 | 2021113302017 |
11 | 70a170850117 |
12 | 287856909595 |
13 | 1187897994a4 |
14 | 6db72977b45 |
15 | 3789185abb2 |
hex | 1d693bd8c01 |
2021113302017 has 2 divisors, whose sum is σ = 2021113302018. Its totient is φ = 2021113302016.
The previous prime is 2021113302001. The next prime is 2021113302037. The reversal of 2021113302017 is 7102033111202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2020878323776 + 234978241 = 1421576^2 + 15329^2 .
It is a cyclic number.
It is not a de Polignac number, because 2021113302017 - 24 = 2021113302001 is a prime.
It is a super-2 number, since 2×20211133020172 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2021113301983 and 2021113302001.
It is not a weakly prime, because it can be changed into another prime (2021113302037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010556651008 + 1010556651009.
It is an arithmetic number, because the mean of its divisors is an integer number (1010556651009).
Almost surely, 22021113302017 is an apocalyptic number.
It is an amenable number.
2021113302017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021113302017 is an equidigital number, since it uses as much as digits as its factorization.
2021113302017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 2021113302017 its reverse (7102033111202), we get a palindrome (9123146413219).
The spelling of 2021113302017 in words is "two trillion, twenty-one billion, one hundred thirteen million, three hundred two thousand, seventeen".
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