2021120000113 has 4 divisors (see below), whose sum is σ = 2034504900928. Its totient is φ = 2007735099300.

The previous prime is 2021120000087. The next prime is 2021120000149. The reversal of 2021120000113 is 3110000211202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2021120000113 - 2²⁵ = 2021086445681 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2021120000093 and 2021120000102.

It is not an unprimeable number, because it can be changed into a prime (2021120100113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6692450181 + ... + 6692450482.

It is an arithmetic number, because the mean of its divisors is an integer number (508626225232).

Almost surely, 2^{2021120000113} is an apocalyptic number.

It is an amenable number.

2021120000113 is a deficient number, since it is larger than the sum of its proper divisors (13384900815).

2021120000113 is a wasteful number, since it uses less digits than its factorization.

2021120000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13384900814.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 2021120000113 its reverse (3110000211202), we get a palindrome (5131120211315).

The spelling of 2021120000113 in words is "two trillion, twenty-one billion, one hundred twenty million, one hundred thirteen", and thus it is an aban number.