Base | Representation |
---|---|
bin | 11101011010010100001… |
… | …100110101000011000111 |
3 | 21011012212101202211200220 |
4 | 131122110030311003013 |
5 | 231103223440120403 |
6 | 4144253513435423 |
7 | 266010156133113 |
oct | 35322414650307 |
9 | 7135771684626 |
10 | 2021121020103 |
11 | 70a1751418a9 |
12 | 28785940bb73 |
13 | 11878b26c4c3 |
14 | 6db739c6743 |
15 | 37892382953 |
hex | 1d6943350c7 |
2021121020103 has 16 divisors (see below), whose sum is σ = 2877389687040. Its totient is φ = 1258857984384.
The previous prime is 2021121020081. The next prime is 2021121020119. The reversal of 2021121020103 is 3010201211202.
It is not a de Polignac number, because 2021121020103 - 213 = 2021121011911 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2021121020123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 340597138 + ... + 340603071.
It is an arithmetic number, because the mean of its divisors is an integer number (179836855440).
Almost surely, 22021121020103 is an apocalyptic number.
2021121020103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2021121020103 is a deficient number, since it is larger than the sum of its proper divisors (856268666937).
2021121020103 is a wasteful number, since it uses less digits than its factorization.
2021121020103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 681200278.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 2021121020103 its reverse (3010201211202), we get a palindrome (5031322231305).
The spelling of 2021121020103 in words is "two trillion, twenty-one billion, one hundred twenty-one million, twenty thousand, one hundred three".
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