Base | Representation |
---|---|
bin | 101101111101001000100000… |
… | …010100010001110111011011 |
3 | 222111121211021100220221101111 |
4 | 231331020200110101313123 |
5 | 202442410123434432024 |
6 | 1553505252111001151 |
7 | 60400122234215236 |
oct | 5575104024216733 |
9 | 874554240827344 |
10 | 202113113202139 |
11 | 59443765363077 |
12 | 1a802a608091b7 |
13 | 88a1252cbb399 |
14 | 37ca480d2a41d |
15 | 185765c619a94 |
hex | b7d220511ddb |
202113113202139 has 2 divisors, whose sum is σ = 202113113202140. Its totient is φ = 202113113202138.
The previous prime is 202113113202101. The next prime is 202113113202157. The reversal of 202113113202139 is 931202311311202.
It is a happy number.
202113113202139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 202113113202139 - 219 = 202113112677851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 202113113202139.
It is not a weakly prime, because it can be changed into another prime (202113113262139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101056556601069 + 101056556601070.
It is an arithmetic number, because the mean of its divisors is an integer number (101056556601070).
Almost surely, 2202113113202139 is an apocalyptic number.
202113113202139 is a deficient number, since it is larger than the sum of its proper divisors (1).
202113113202139 is an equidigital number, since it uses as much as digits as its factorization.
202113113202139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 202113113202139 in words is "two hundred two trillion, one hundred thirteen billion, one hundred thirteen million, two hundred two thousand, one hundred thirty-nine".
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