Base | Representation |
---|---|
bin | 101101111101001000100000… |
… | …010100010011110100011111 |
3 | 222111121211021100221100100221 |
4 | 231331020200110103310133 |
5 | 202442410123440211033 |
6 | 1553505252111102211 |
7 | 60400122234250462 |
oct | 5575104024236437 |
9 | 874554240840327 |
10 | 202113113210143 |
11 | 59443765369093 |
12 | 1a802a60811967 |
13 | 88a1252cc1c15 |
14 | 37ca480d2d2d9 |
15 | 185765c61c12d |
hex | b7d220513d1f |
202113113210143 has 2 divisors, whose sum is σ = 202113113210144. Its totient is φ = 202113113210142.
The previous prime is 202113113210117. The next prime is 202113113210147. The reversal of 202113113210143 is 341012311311202.
202113113210143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 202113113210143 - 217 = 202113113079071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (202113113210147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101056556605071 + 101056556605072.
It is an arithmetic number, because the mean of its divisors is an integer number (101056556605072).
Almost surely, 2202113113210143 is an apocalyptic number.
202113113210143 is a deficient number, since it is larger than the sum of its proper divisors (1).
202113113210143 is an equidigital number, since it uses as much as digits as its factorization.
202113113210143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 202113113210143 its reverse (341012311311202), we get a palindrome (543125424521345).
The spelling of 202113113210143 in words is "two hundred two trillion, one hundred thirteen billion, one hundred thirteen million, two hundred ten thousand, one hundred forty-three".
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