Base | Representation |
---|---|
bin | 11101011010010100111… |
… | …010100001111001111111 |
3 | 21011012220020022111110121 |
4 | 131122110322201321333 |
5 | 231103240022002234 |
6 | 4144255022315411 |
7 | 266010363020626 |
oct | 35322472417177 |
9 | 7135806274417 |
10 | 2021133000319 |
11 | 70a180984804 |
12 | 287861428b67 |
13 | 1187908a54a4 |
14 | 6db754246bd |
15 | 3789344c4b4 |
hex | 1d694ea1e7f |
2021133000319 has 2 divisors, whose sum is σ = 2021133000320. Its totient is φ = 2021133000318.
The previous prime is 2021133000301. The next prime is 2021133000331. The reversal of 2021133000319 is 9130003311202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2021133000319 - 25 = 2021133000287 is a prime.
It is a super-2 number, since 2×20211330003192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2021133000293 and 2021133000302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2021133007319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010566500159 + 1010566500160.
It is an arithmetic number, because the mean of its divisors is an integer number (1010566500160).
Almost surely, 22021133000319 is an apocalyptic number.
2021133000319 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021133000319 is an equidigital number, since it uses as much as digits as its factorization.
2021133000319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 2021133000319 in words is "two trillion, twenty-one billion, one hundred thirty-three million, three hundred nineteen", and thus it is an aban number.
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