Base | Representation |
---|---|
bin | 1001001100001111110010… |
… | …00101100001001100000001 |
3 | 2122120020201001001111012211 |
4 | 10212013321011201030001 |
5 | 10122123134011213441 |
6 | 110553133100022121 |
7 | 4154161130113303 |
oct | 446077105411401 |
9 | 78506631044184 |
10 | 20212000101121 |
11 | 6492952149884 |
12 | 2325279b31941 |
13 | b37ca27a175a |
14 | 4dc3a1d85973 |
15 | 250b61a9aa81 |
hex | 1261f9161301 |
20212000101121 has 4 divisors (see below), whose sum is σ = 20642042656512. Its totient is φ = 19781957545732.
The previous prime is 20212000101119. The next prime is 20212000101127. The reversal of 20212000101121 is 12110100021202.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20212000101121 - 21 = 20212000101119 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20212000101127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215021277625 + ... + 215021277718.
It is an arithmetic number, because the mean of its divisors is an integer number (5160510664128).
Almost surely, 220212000101121 is an apocalyptic number.
It is an amenable number.
20212000101121 is a deficient number, since it is larger than the sum of its proper divisors (430042555391).
20212000101121 is an equidigital number, since it uses as much as digits as its factorization.
20212000101121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 430042555390.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 20212000101121 its reverse (12110100021202), we get a palindrome (32322100122323).
The spelling of 20212000101121 in words is "twenty trillion, two hundred twelve billion, one hundred one thousand, one hundred twenty-one".
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