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20212020113 is a prime number
BaseRepresentation
bin10010110100101110…
…101111001110010001
31221011121111000011112
4102310232233032101
5312343234120423
613141341423105
71313605223225
oct226456571621
957147430145
1020212020113
11863218195a
123b00b6aa95
131ba15b011c
14d9a516785
157d469ba78
hex4b4baf391

20212020113 has 2 divisors, whose sum is σ = 20212020114. Its totient is φ = 20212020112.

The previous prime is 20212020091. The next prime is 20212020131. The reversal of 20212020113 is 31102021202.

It is a happy number.

Together with next prime (20212020131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18362418064 + 1849602049 = 135508^2 + 43007^2 .

It is a cyclic number.

It is not a de Polignac number, because 20212020113 - 210 = 20212019089 is a prime.

It is not a weakly prime, because it can be changed into another prime (20212020133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10106010056 + 10106010057.

It is an arithmetic number, because the mean of its divisors is an integer number (10106010057).

Almost surely, 220212020113 is an apocalyptic number.

It is an amenable number.

20212020113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20212020113 is an equidigital number, since it uses as much as digits as its factorization.

20212020113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 20212020113 its reverse (31102021202), we get a palindrome (51314041315).

The spelling of 20212020113 in words is "twenty billion, two hundred twelve million, twenty thousand, one hundred thirteen".