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2021213140333 is a prime number
BaseRepresentation
bin11101011010011001101…
…100001111010101101101
321011020002211010000220021
4131122121230033111231
5231103421030442313
64144311004122141
7266012355136162
oct35323154172555
97136084100807
102021213140333
1170a212141122
12287884236351
131187a438450a
146db81d26069
153789a4cc78d
hex1d699b0f56d

2021213140333 has 2 divisors, whose sum is σ = 2021213140334. Its totient is φ = 2021213140332.

The previous prime is 2021213140321. The next prime is 2021213140367. The reversal of 2021213140333 is 3330413121202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1510141138884 + 511072001449 = 1228878^2 + 714893^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2021213140333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2021213140298 and 2021213140307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2021213140313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010606570166 + 1010606570167.

It is an arithmetic number, because the mean of its divisors is an integer number (1010606570167).

Almost surely, 22021213140333 is an apocalyptic number.

It is an amenable number.

2021213140333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2021213140333 is an equidigital number, since it uses as much as digits as its factorization.

2021213140333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 2021213140333 its reverse (3330413121202), we get a palindrome (5351626261535).

The spelling of 2021213140333 in words is "two trillion, twenty-one billion, two hundred thirteen million, one hundred forty thousand, three hundred thirty-three".