Base | Representation |
---|---|
bin | 1001001100010000011101… |
… | …10110111010100000010101 |
3 | 2122120021122111101010212011 |
4 | 10212020032312322200111 |
5 | 10122124411013341123 |
6 | 110553233225024221 |
7 | 4154203153630255 |
oct | 446101666724025 |
9 | 78507574333764 |
10 | 20212365371413 |
11 | 649301a353856 |
12 | 2325360325071 |
13 | b38030373317 |
14 | 4dc3d86a9965 |
15 | 250b83b9de0d |
hex | 12620edba815 |
20212365371413 has 2 divisors, whose sum is σ = 20212365371414. Its totient is φ = 20212365371412.
The previous prime is 20212365371389. The next prime is 20212365371417. The reversal of 20212365371413 is 31417356321202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11287705039524 + 8924660331889 = 3359718^2 + 2987417^2 .
It is a cyclic number.
It is not a de Polignac number, because 20212365371413 - 217 = 20212365240341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20212365371417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10106182685706 + 10106182685707.
It is an arithmetic number, because the mean of its divisors is an integer number (10106182685707).
Almost surely, 220212365371413 is an apocalyptic number.
It is an amenable number.
20212365371413 is a deficient number, since it is larger than the sum of its proper divisors (1).
20212365371413 is an equidigital number, since it uses as much as digits as its factorization.
20212365371413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 40.
The spelling of 20212365371413 in words is "twenty trillion, two hundred twelve billion, three hundred sixty-five million, three hundred seventy-one thousand, four hundred thirteen".
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