20213000113 has 4 divisors (see below), whose sum is σ = 20358417520. Its totient is φ = 20067582708.

The previous prime is 20213000107. The next prime is 20213000161. The reversal of 20213000113 is 31100031202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20213000113 - 2⁵ = 20213000081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20213000093 and 20213000102.

It is not an unprimeable number, because it can be changed into a prime (20213000183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72708495 + ... + 72708772.

It is an arithmetic number, because the mean of its divisors is an integer number (5089604380).

Almost surely, 2^20213000113 is an apocalyptic number.

It is an amenable number.

20213000113 is a deficient number, since it is larger than the sum of its proper divisors (145417407).

20213000113 is a wasteful number, since it uses less digits than its factorization.

20213000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145417406.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 20213000113 its reverse (31100031202), we get a palindrome (51313031315).

The spelling of 20213000113 in words is "twenty billion, two hundred thirteen million, one hundred thirteen", and thus it is an aban number.