Base | Representation |
---|---|
bin | 1001001100010011110001… |
… | …01001011011111001111111 |
3 | 2122120110020012001221122221 |
4 | 10212021320221123321333 |
5 | 10122142024344114403 |
6 | 110554125310150211 |
7 | 4154265144624061 |
oct | 446117051337177 |
9 | 78513205057587 |
10 | 20214140223103 |
11 | 64938501a1132 |
12 | 23257767b2367 |
13 | b38253c99818 |
14 | 4dc5262b7731 |
15 | 250c398dadbd |
hex | 126278a5be7f |
20214140223103 has 2 divisors, whose sum is σ = 20214140223104. Its totient is φ = 20214140223102.
The previous prime is 20214140223097. The next prime is 20214140223119. The reversal of 20214140223103 is 30132204141202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20214140223103 - 25 = 20214140223071 is a prime.
It is a super-2 number, since 2×202141402231032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20214140223803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10107070111551 + 10107070111552.
It is an arithmetic number, because the mean of its divisors is an integer number (10107070111552).
Almost surely, 220214140223103 is an apocalyptic number.
20214140223103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20214140223103 is an equidigital number, since it uses as much as digits as its factorization.
20214140223103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 20214140223103 its reverse (30132204141202), we get a palindrome (50346344364305).
The spelling of 20214140223103 in words is "twenty trillion, two hundred fourteen billion, one hundred forty million, two hundred twenty-three thousand, one hundred three".
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