Base | Representation |
---|---|
bin | 101101111101100100110000… |
… | …100010000110010110001111 |
3 | 222111201201120121000112210020 |
4 | 231331210300202012112033 |
5 | 202443404241202002003 |
6 | 1553531230254313223 |
7 | 60402245064055011 |
oct | 5575446042062617 |
9 | 874651517015706 |
10 | 202143450031503 |
11 | 59455612745a82 |
12 | 1a8089084b8813 |
13 | 88a40790a78a6 |
14 | 37cbb1bdb41b1 |
15 | 1858335ac9d53 |
hex | b7d93088658f |
202143450031503 has 8 divisors (see below), whose sum is σ = 269728630781616. Its totient is φ = 134660284651200.
The previous prime is 202143450031459. The next prime is 202143450031519. The reversal of 202143450031503 is 305130054341202.
202143450031503 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-202143450031503 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (202143450031403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25503837828 + ... + 25503845753.
It is an arithmetic number, because the mean of its divisors is an integer number (33716078847702).
Almost surely, 2202143450031503 is an apocalyptic number.
202143450031503 is a deficient number, since it is larger than the sum of its proper divisors (67585180750113).
202143450031503 is a wasteful number, since it uses less digits than its factorization.
202143450031503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51007684905.
The product of its (nonzero) digits is 43200, while the sum is 33.
The spelling of 202143450031503 in words is "two hundred two trillion, one hundred forty-three billion, four hundred fifty million, thirty-one thousand, five hundred three".
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