Base | Representation |
---|---|
bin | 10010110100111010… |
… | …010010110011111111 |
3 | 1221011211011220122222 |
4 | 102310322102303333 |
5 | 312400023040341 |
6 | 13141530355555 |
7 | 1313643041201 |
oct | 226472226377 |
9 | 57154156588 |
10 | 20215049471 |
11 | 8633960961 |
12 | 3b01b8bbbb |
13 | 1ba2100c46 |
14 | d9aaa4771 |
15 | 7d4a9944b |
hex | 4b4e92cff |
20215049471 has 4 divisors (see below), whose sum is σ = 20244647592. Its totient is φ = 20185451352.
The previous prime is 20215049453. The next prime is 20215049507. The reversal of 20215049471 is 17494051202.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 17494051202 = 2 ⋅8747025601.
It is a cyclic number.
It is not a de Polignac number, because 20215049471 - 234 = 3035180287 is a prime.
It is a super-3 number, since 3×202150494713 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20215049441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14798036 + ... + 14799401.
It is an arithmetic number, because the mean of its divisors is an integer number (5061161898).
Almost surely, 220215049471 is an apocalyptic number.
20215049471 is a deficient number, since it is larger than the sum of its proper divisors (29598121).
20215049471 is an equidigital number, since it uses as much as digits as its factorization.
20215049471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29598120.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 20215049471 in words is "twenty billion, two hundred fifteen million, forty-nine thousand, four hundred seventy-one".
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