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202200002013 = 367400000671
BaseRepresentation
bin1011110001010000001…
…1110010110111011101
3201022220122222100220110
42330110003302313131
511303101200031023
6232520035440233
720415463442022
oct2742403626735
9638818870813
10202200002013
11788306a2289
1233230456079
13160b5051709
149b0235d549
1553d6691a93
hex2f140f2ddd

202200002013 has 4 divisors (see below), whose sum is σ = 269600002688. Its totient is φ = 134800001340.

The previous prime is 202200001987. The next prime is 202200002029. The reversal of 202200002013 is 310200002202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 202200002013 - 29 = 202200001501 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 202200002013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202200002083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33700000333 + ... + 33700000338.

It is an arithmetic number, because the mean of its divisors is an integer number (67400000672).

Almost surely, 2202200002013 is an apocalyptic number.

It is an amenable number.

202200002013 is a deficient number, since it is larger than the sum of its proper divisors (67400000675).

202200002013 is an equidigital number, since it uses as much as digits as its factorization.

202200002013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67400000674.

The product of its (nonzero) digits is 48, while the sum is 12.

Adding to 202200002013 its reverse (310200002202), we get a palindrome (512400004215).

The spelling of 202200002013 in words is "two hundred two billion, two hundred million, two thousand, thirteen".

Divisors: 1 3 67400000671 202200002013