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202204142013 = 367401380671
BaseRepresentation
bin1011110001010001001…
…1100101100110111101
3201022220221202200220210
42330110103211212331
511303103230021023
6232520304303033
720415543564006
oct2742423454675
9638827680823
10202204142013
1178832a6a775
1233231911a79
13160b5b70c13
149b02b1a1ad
1553d6c0d593
hex2f144e59bd

202204142013 has 4 divisors (see below), whose sum is σ = 269605522688. Its totient is φ = 134802761340.

The previous prime is 202204142011. The next prime is 202204142017. The reversal of 202204142013 is 310241402202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 202204142013 - 21 = 202204142011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202204142011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33700690333 + ... + 33700690338.

It is an arithmetic number, because the mean of its divisors is an integer number (67401380672).

Almost surely, 2202204142013 is an apocalyptic number.

It is an amenable number.

202204142013 is a deficient number, since it is larger than the sum of its proper divisors (67401380675).

202204142013 is an equidigital number, since it uses as much as digits as its factorization.

202204142013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67401380674.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 202204142013 its reverse (310241402202), we get a palindrome (512445544215).

The spelling of 202204142013 in words is "two hundred two billion, two hundred four million, one hundred forty-two thousand, thirteen".

Divisors: 1 3 67401380671 202204142013